在图4所示的网络拓扑中，假设自治系统AS3和AS2内部运行OSPF,AS1和AS4内部运行RIP。各自治系统间用BGP作为路由协议，并假设AS2和AS4之间没有物理链路。则路由器3c基于（作答此空）协议学习到网络x的可达性信息。1d通过（）学习到x的可达性信息。
- A.OSPF
- B.RIP
- C.EBGP
- D.IBGP
正确答案及解析
正确答案
解析
参见《网络规划设计师5天修炼》BGP部分。在BGP中，两个路由器之间的相邻连接称为对等体（Peer）连接，两个路由器互为对等体。如果路由器对等体在同一个AS中，就称为IBGP对等体；否则称为EBGP对等体。所以路由器3c基于EBGP协议学习到网络x的可达性信息。
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