在异步通信中,每个字符包含1位起始位、7位数据位、1位奇偶位和2位终止位,每秒钟传送200个字符,采用QPSK调制,则码元速率为( )波特。
- A.500
- B.550
- C.1100
- D.2200
正确答案及解析
正确答案
C
解析
每秒200字符,数据速率为2200bps,采用QPSK调制,码元种类数为4,所以R=Blog2N,码元速率为1100波特。
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